# # Two Sum

Easy

Given an array of integers, return indices of the two numbers such that they add up to a specific target.

You may assume that each input would have exactly one solution, and you may not use the same element twice.

## # Examples:

Given nums = [2, 7, 11, 15], target = 9,

Because nums[0] + nums[1] = 2 + 7 = 9,
return [0, 1].


## # Solution

/**
* @param {number[]} nums
* @param {number} target
* @return {number[]}
*/
var twoSum = function(nums, target) {
var hash = {}
for (let i = 0; i < nums.length; i++) {
const num = nums[i]
if (hash[num] !== undefined) {
return [hash[num], i]
} else {
hash[target - num] = i
}
}
return []
}